Thursday, January 24, 2013

Number Divisible by 4

A number divisible by 4 means nothing but a Division operation. Each and every number should divided by 4,that is called number divisible by 4.Four is a even number, When the number is even we can get the even integer numbers ,When we divided the odd number mean We cannot get the real number ,Only got the fraction numbers. Division is a one of the arithmetic operation. Arithmetic operations 1) Addition  2) Subtraction 3) Multiplication 4) Division

Step by Step Number Divisible by 4:


Form of Manual division method,

a / b = c ,where

Here number divide by 4 so we can use the constant of divisor 4

a = dividend.

b = 4 is called as divisor.

c = quotient.

Example:

12 / 4 = 3

Example problem 1: 32 divide by 4

32 divide by 4

Solution:


From the problem

32 is a dividend

4 is a divisor

In numerically it can written as 32/4

Step 1:

First we find the how many 4’s are available in the dividend

Step 2:

After find the  no of multiples in the dividend, We got the answer

32/4=8

Four is the quotient of 8

Remaining should be zero

Using Algebra Division Number Divisible by 4

Example 2: Using algebra division Number divisible by 4

Algebra division example using polynomial:

4x2+4x+4 / 4

4x2+4x+4 is dividend

4 is divisor

x2+x+1   is quotient of (4x2+4x+4) / 4

Example algebra division problem:

Division of: (42+4x+4)/4

Step 1:

(4X2+4x+4) is dividend

4 is the divisor

First we can arrange the terms

Like x2+x3+x mean we can change x3+x2+x

Step 2:

Now  we can  divide the first term of the dividend

by the1st  term of the divisor, it mean 4x2/4=x2 .It gives the first terms of quotient.

Step 3:

Now we got the first term of  quotient and then subtract the Multiplication of first terms quotient and dividend 4x2-4=x2

Step 4:

Again we can  divide the second term term of the dividend   by the first term of the divisor 4, it mean   4x/4 =1 .It should provide the second terms  after then multiply the first term with quotient after  then subtract

Step 5:

Same procedure for the constant term Now we got the final answer  x2+x+1

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